Tentukan PGL yang melalui titik (-6,-1) dan (8,-3)
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Materi : Persamaan Garis Lurus
Titik ( x¹ = -6 , y¹ = -1 )
Titik ( x² = 8 , y² = -3 )
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( x - x¹ )/( x² - x¹ ) = ( y - y¹ )/( y² - y¹ )
( x + 6 )/( 8 + 6 ) = ( y + 1 )/( - 3 + 1 )
( x + 6 )/14 = ( y + 1 )/( -2 )
-2( x + 6 ) = 14( y + 1 )
- 2x - 12 = 14y + 14
2x + 14y + 26 = 0
Semoga bisa membantu
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